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Site updated on May 14, 2016

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Double Heterozygous for Snow X Het Albino

 

The Punnett Square     

[or reverse it for Heterozygous axanthic]

Double Heterozygous for snow = a+b+ X Heterozygous albino = a+++

The following are averages over a long period of time (out of a possible 16) you get:

2 Normal = ++++
4 Heterozygous albino = a+++
2
Heterozygous axanthic = b+++
4 D
ouble Heterozygous snow = a+b+
2 Albino = aa
++
2 Albino
Heterozygous for axanthic = aab+

 

  ++ b+ a+ ab
++ ++++ b+++ a+++ a+b+
++ ++++ b+++ a+++ a+b+
a+ a+++ a+b+ aa++ aab+
a+ a+++ a+b+ aa++ aab+

 

This page updated on Saturday, May 14, 2016 01:29 PM .

     

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